E=mc2; M=3; C=6 Solve For E. | Wyzant Ask An Expert

E=MC2 E=MC² E=MC^2. M=E/C2 M=E/C² M=E/C^2. But why are the two solutions for the value of C in Einstein's famous equation. An appeal to any mathematitions or...The full and general relationship, then, for any moving object, isn't just E = mc 2, but that E 2 = m 2 c 4 + p 2 c 2. (Where p is momentum.) Only by generalizing things to include energyDivide both sides by c^2 so as to leave m on its own on one side of the equation and then m = E/c^2 Similarly velocity (v) = distance (d) divided by time (t) eg miles per hour or feet per seconddivide by c^2 [I assume you left that "^" symbol out]. m = E / c^2. Otherwise this is a trick question and m = E / 2c.If you solve E = mc^2 for m you do not get m = E-c^2. m and c are multiplied together, so division is required. The correct answer is m = E/ (c^2). I suggest that you master basic algebra (a ninth grade class), and few more classes before you attempt to learn higher level science and mathematics. 2.4K vi! ews

The Three Meanings Of E=mc^2, Einstein's Most Famous Equation

"How EINSTEIN Arrived at E=MC2" Dear Friend: Most people think Einstein was a genius. Even though he did poorly in school, it is generally assumed that Einstein became a genius later on. It's also widely believed that he used superior intellect and complex mathematical reasoning to finally arrive at E=MC2.The formula for converting mass to energy is E = mc2. Solve the formula for m.e = mc^2 m = 3 c = 6 e = 3 (6^2)where f c is the force acting on a particle with a total energy e. Solving Equation (40) for e gives the alternate relationship (41) Relationship of f c to e . where e is the total energy of a particle acted on by force f c. Doing the same thing with the right sides of Equations (38) and (36) then gives (42)

Solve the equation for m where E = mc2? | Yahoo Answers

Solving Equations Solve each equation or formula for the specified variable. 15. E = mc2, for m 2d +1 16. c=-20+1, ford 17. h = vt - gt2, for v 18.E equals MC2 , for m. E=mc2, for m. Experienced teacher willing to help all students. See tutors like this. See tutors like this. m=E/C^2 is the correct equation solving for m.Simple and best practice solution for E=Mc2 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework. If it's not what You are looking for type in the equation solver your own equation and let us solve it.e = mc2 e = m c 2 Rewrite the equation as mc2 = e m c 2 = e. mc2 = e m c 2 = e Divide each term by m m and simplify.Ever since high school I've wondered what the speed of light has to do with Einstein's formula E = MC2 Solving the equation for C, you get C = √ E / M

Introduction

One of probably the most ordinary things about Einstein's energy- mass equivalence equation is its simplicity. However, we still want to be sure we are using the right kind devices when fixing the equation, and that we perceive the answer. The purpose of this web page is to solve the equation as it's and give some concept of the large quantity of energy locked up in even the smallest amount of mass.

The Components of the Equation

If we smash the equation E = mc 2 into its parts and write out the phrases fully we get:

E = energy (measured in joules) m = mass (measured in kilograms) c = the speed of light (186,000 miles per 2nd, or Three x 10 8 ms -1 )

We will now examine each and every of the terms in slightly more detail.

Energy is measured in joules (J). How much energy is one joule? Not very much in point of fact. If you pick up a large apple and raise it above your head you are going to have used round one joule of calories in the procedure. On the other hand, we use up large amounts of energy each and every time we switch on a mild. A A hundred watt light bulb makes use of 100 joules of energy every second, i.e. one watt is one joule in line with second.

Energy

Mass

The velocity of light

Mass is a measure of a frame's resistance to acceleration. The greater the mass the better the resistance to acceleration, as any person who has ever attempted to push a heavy object is aware of. However, for our functions we will also think of mass as the quantity of topic in an object. Mass is measured in kilograms (kg), with 1 kg about the same as 2.2 kilos. Note that we haven't said what the mass consists of. In truth, it might be anything else. It doesn't subject if we use iron, plastic, wood, rock or gravy. The equation tells us that regardless of the mass is it may be turned into calories (whether it is sensible to in truth achieve this is some other topic and is handled in different pages on this sequence). The velocity of light is very close to 186,300 miles in line with second (300,000 km in line with second). In order to make the equation "work" we want to convert those numbers into units that are more suited for our purposes. In physics speeds are measured in metres consistent with second. This is normally abbreviated to ms -1 ; that is: "metres times seconds to the minus one". Don't fear in the event you don't perceive this notation. We may just similarly write m/s however the usage of ms -1 makes the maths more uncomplicated ultimately. Likewise, lets either say that the rate of light is 300,000,000 metres per second, or, as is extra same old, specific the similar determine in scientific notation: 3 x 10 8 ms -1 .

Now that we have got everything in order let's have a cross at fixing the equation. We will use a mass of one kg to keep issues simple and I will show the entire workings of the equation. So, with 1 kg of mass (around 2.2 kilos) we get:

Solving the Basic Equation

Note how the devices had been dealt with and that kg m 2 s -2 is the similar as joules (even if a rigorous evidence of that is outside the scope of these pages).

So from 1 kg of matter, any topic, we get Nine x 10 16 joules of energy. Writing that out totally we get:

90,000,000,000,000,000 joules

That is a large number of calories! For example, if we converted 1 kg of mass into energy and used all of it to energy a A hundred watt mild bulb how long may just we stay it lit for? In order to respond to the query the first thing to do is divide the outcome by way of watts (take into account that 1 watt is 1 joule consistent with 2d):

9 x 10 16 J / One hundred W = 9 x 10 14 seconds

That's a large number of seconds, however how lengthy is that during years? A year (365.25 days) is 31,557,600 seconds, so:

9 x 10 14 seconds / 31,557,600 seconds = 28,519,279 years

That is a very long time!

Of direction, converting mass into energy is not rather that easy, and excluding with some tiny debris in experimental eventualities has never been carried out with 100% efficiency. Perhaps that's simply as smartly.

Conclusion

We have seen that the E = mc 2 equation is straightforward to solve as it is and that for even a small amount of mass an enormous quantity of calories can, no less than in idea, be launched. Other pages in this series show how the energy can be launched in sensible tactics, in addition to deriving the equation in both simple and advanced terms.

E = mc 2 – Numerous energy from a small mass