a.) Determine the [H3O+] of a 0.170 M solution of formic acid (Ka=1.8×10−4). Express your answer using two significant figures. b.) Determine pH of this solution of formic acid. Express your answer to two decimal places. c.) Amphetamine (C9H13N) is a weak base with a pKb of 4.2.Formic acid, HCO2H, is a weak acid. Write a net ionic equation for the reaction of formic acid and aqueous potassium hydroxide. Chemistry. Oxalic acid, found in the leaves of rhubarb and other plants, is a diprotic acid. H2C2O4 + H2O ↔ H3O+ + HC2O4- Ka1= ? HC2O4- + H2O ↔ H3O+ + C2O42- Ka2 = ? An aqueous solution that is 1.05 M H2C2O4 has pHDetermine the [H3O+] of a 0.220 M solution of formic acid. Express your answer using two significant figures. Part B Determine pH of this solution of formic acid. Express your answer to two decimal places. 3) Determine the pH of an HF solution of each of the following concentrations. A 5.30102 M Express your answer to two decimal places. B 2Get the detailed answer: determine the [h3o+] of a 0.210 m solution of formic acid. Get the detailed answer: determine the [h3o+] of a 0.210 m solution of formic acid. Switch to. Home. Your dashboard and recommendations. Booster Classes. Personalized courses, with or without credits. Homework Help. 3.7 million tough questions answeredDetermine the [H3O+] of a 0.210 M solution of formic acid.? Also... Determine pH of this solution of formic acid. I am not understanding what I am doing wrong but I keep getting the answer 2.21. Please help! Answer Save. 2 Answers. Relevance? Lv 7. 5 years ago (pKa) for formic acid =3.77.
Determine the [H3O^+] of a 0.240 M solution of formic acid.
Associated to determine the [h3o+] of a 0.250 m solution of formic acid., Acid reflux disorder disease and heartburn could potentially cause serious actual physical and emotional pains into the sufferer. Physically you will be confronted with the problem of ways to address regular burning sensations as part of your upper body and stomach pains.For part (a): pH_"sol" = 2.22 I will show you how to solve part (a), so that you can use this example to solve part (b) on your own. So, you're dealing with formic acid, "HCOOH", a weak acid that does not dissociate completely in aqueous solution. This means that an equilibrium will be established between the unionized and ionized forms of the acid.Answer to Part A Determine (H3O+] of a 0.250 M solution of formic acid (Ka = 1.8 x 10-4). Express your answer using two significan...How to solve: Determine the [H3O+] of a 0.210 M solution of formic acid. Determine pH of this solution of formic acid. By signing up, you'll get...
Determine the [H3O+] of a 0.220 M solution of formic acid
What is the pH of a .200 M solution of formic acid? Chemistry Acids and Bases pH calculations. 1 Answer anor277 Oct 18, 2016 And #pK_a# for formic acid is? #pH=2.23# Explanation: #HC(=O)OH + H_2O rightleftharpoons H_3O^+ + HC(=O)O^-# How can I calculate the pH of a solution? See all questions in pH calculations Impact of this questionSo the concentration of the HCOOH is written as [0.05 - x]. At this point, the argument is usually made that the ionized fraction of the formic acid is so small compared to the original concentration of the acid, that the "x" lost by the formic acid can be ignored. If we were to do this the solution would be really simple and consist of solving;Get the detailed answer: Determine the [H3O+] of a 0.240 M solution of formic acid. The Ka of formic acid is 1.8 x 10-4.Determine [H3O+] of a 0.250 M solution of formic acid (K= 1.8 x 10-4). Express your answer using two significant figures. View Available Hint(s) VO ΟΙ ΑΣφ.Determine the H3O+ of a 0.230 M solution of formic acid?
Formic acid, HCOOH, is a susceptible acid and is partly ionized.
HCOOH(aq) <==> H+(aq) + HCOO-(aq) .............. Ka = 1.77x10^-4
0.250M .............. ..?M
Ka = [H+] HCOO-] / [HCOOH]
1.77x10^-4 = x² / (0.250-x)
x = 0.00686
[H+] = 0.00686M
pH = -log[H+] = 2.183 ........... to three significant digits
Note: When taking the log of a quantity, best the digits to the proper of the decimal replicate the precision of the unique dimension.
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